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求f（x1x2…xn=^nПr=1f（xr）（x1x2…xr—1Xr＋1…Xn）^β的解f（x）
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求f（x1x2…xn=^nПr=1f（xr）（x1x2…xr—1Xr＋1…Xn）^β的解f（x）
常颖中
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白玉芳
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1997-01-01
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Acta Scientiarum Naturalium Universitatis Sunyatseni
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Keywords
Mathematics
Combinatorics
Discrete mathematics
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